python操作gmail
import imaplib, re class pygmail( object ): def __init__( self ): self .IMAP_SERVER = 'imap.gmail.com' self .IMAP_PORT = 993 self .M = None self .response = None self .mailboxes = [] def login( self , username, password): self .M = imaplib.IMAP4_SSL( self .IMAP_SERVER, self .IMAP_PORT) rc, self .response = self .M.login(username, password) return rc def get_mailboxes( self ): rc, self .response = self .M. list () for item in self .response: self .mailboxes.append(item.split()[ - 1 ]) return rc def get_mail_count( self , folder = 'Inbox' ): rc, self .response = self .M.select(folder) return self .response[ 0 ] def get_unread_count( self , folder = 'Inbox' ): rc, self .response = self .M.status(folder, "(UNSEEN)" ) unreadCount = re.search( "UNSEEN (\d+)" , self .response[ 0 ]).group( 1 ) return unreadCount def get_imap_quota( self ): quotaStr = self .M.getquotaroot( "Inbox" )[ 1 ][ 1 ][ 0 ] r = re. compile ( '\d+' ).findall(quotaStr) if r = = []: r.append( 0 ) r.append( 0 ) return float (r[ 1 ]) / 1024 , float (r[ 0 ]) / 1024 def get_mails_from( self , uid, folder = 'Inbox' ): status, count = self .M.select(folder, readonly = 1 ) status, response = self .M.search( None , 'FROM' , uid) email_ids = [e_id for e_id in response[ 0 ].split()] return email_ids def get_mail_from_id( self , id ): status, response = self .M.fetch( id , '(body[header.fields (subject)])' ) return response def rename_mailbox( self , oldmailbox, newmailbox): rc, self .response = self .M.rename(oldmailbox, newmailbox) return rc def create_mailbox( self , mailbox): rc, self .response = self .M.create(mailbox) return rc def delete_mailbox( self , mailbox): rc, self .response = self .M.delete(mailbox) return rc def logout( self ): self .M.logout() if __name__ = = "__main__" : demo = pygmail() demo.login( "renwenchao888@gmail.com" , "qqq191430791" ) mailBoxex = demo.get_mailboxes() for i in demo.response: print i demo.logout() ============================================================================= 本文转自被遗忘的博客园博客，原文链接：http://www.cnblogs.com/rollenholt/archive/2011/12/08/2280652.html，如需转载请自行联系原作者
