void Parker::park(bool isAbsolute, jlong time) { // Ideally we'd do something useful while spinning, such // as calling unpackTime(). // Optional fast-path check: // Return immediately if a permit is available. // We depend on Atomic::xchg() having full barrier semantics // since we are doing a lock-free update to _counter. if (Atomic::xchg(0, &_counter) > 0) return;
if (time == 0) { status = pthread_cond_wait (_cond, _mutex) ; } _counter = 0 ; status = pthread_mutex_unlock(_mutex) ; assert_status(status == 0, status, "invariant") ; OrderAccess::fence();
这就是整个park的过程,总结来说就是消耗“许可”的过程。
2、unpark
还是先来看一下JDK源码:
/** * Makes available the permit for the given thread, if it * was not already available. If the thread was blocked on * {@code park} then it will unblock. Otherwise, its next call * to {@code park} is guaranteed not to block. This operation * is not guaranteed to have any effect at all if the given * thread has not been started. * * @param thread the thread to unpark, or {@code null}, in which case * this operation has no effect */ publicstaticvoidunpark(Thread thread){ if (thread != null) UNSAFE.unpark(thread); }
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